martes, 22 de septiembre de 2009

MI CUARTA TAREA DE ALGEBRA¡¡¡¡¡¡¡¡

ENCONTRAR EL VALOR DE x

1.- (5/3)+(4/3) = 2X

resultado.-

(5/3)+(4/3)=3

3/2=x

x=1.5

2.- (6/7)(3/9) + 3X = 4 - (17/5)

resultado.-

(6/7)(3/9)=2/7

4-(17/5)=3/5

3x=3/5-2/7

x=11/35/3

x=0.104

3.- (23/3) + (16/9)X = 23X -12

resultado.-


(23/3)+12=23x+(16/9)x

(23/3)+12=59/3

59/3=(223/9)x

59/3/223/9=x

x=0.793

4.- 12X - 18 + (23/7) = (145/2) -4X

resultado.-

12x+4x=(145/2)-(23/7)+18

(145/2)-(23/7)=969/14

969/14+18=1221/14

16x=1221/14

x=1221/14/16

x=5.450

5.- ((14/2)(15/9) / (125/25)) = 17/3 + (13/4)X

resultado.-

(14/2)(15/9)=35/3

(35/3)/(125/25)=7/3

7/3-17/3=-10/3

-10/3=13/4x

x=-10/3/13/4

x=1.025

6.- 22 -178 + 33/5 -16X = 147 + (248/16)X

resultado.-

22-178+33/5-147=(248/16)x+16x

22-178=200

200+33/5=1033/5

1033/5-147=298/5

298/5=63/2x

298/5/63/2=x

x=1.892

7.- (2)(-3)(5) + 25X = (147/15)X - 248/43 - 223/105

resultado.-

25x-(147/15)x=(2)(-3)(5)-(248/43)-223/105

(2)(-3)=-6

(-6)(5)=-30

-30+248/43=-1042/43

-1042/43+223/105=-22.108

76/5x=-22.108

x=-22.108/76/5

x=-1.454

8.- (45/7)/(198/26) + 28X = 13 + (14/67)(222/111)

resultado.-

(45/7)/(198/26)=65/77

-65/77+13=936/77

(14/67)(222/111)=12.573

x=12.573/28

x=0.449

9.- 48/5 + (2/3)X = 1657 + 345

resultado.-

1657+345=2002

(2/3)x=2002-(48/5)

x=9962/5/2/3

x=2988.6

10.- (2)(-5)(-7)(-8)(9) + 257896 -1247 -5X = 951753 + 456

resultado.-

(2)(-5)=-10

(-10)(-7)=70

(70)(-8)=-560

(-560)(9)=-5040

-5040+257896=252856

252856-1247=251609

251609-951753=-700144

-700144-456=-700600

-700600/5=x

x=-140120

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